SATHEE: Some Basic Concepts of Chemistry - Result Question 9

Some Basic Concepts of Chemistry - Result Question 9

####9. The amount of $sugar (C_{12} H_{22} O_{11})$ required to prepare $2 L$ of its $0.1 M$ aqueous solution is

(2019 Main, 10 Jan II)

(a) $17.1 g$

(b) $68.4 g$

(c) $136.8 g$

(d) $34.2 g$

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Solution:

Molarity $= \frac{Number of moles of solute (n)}{Volume of solution (in L)}$

Also, $n = \frac{w_{B} (g)}{M_{B} (g m o l^{- 1})}$

$∴$ Molarity $= \frac{w_{B} / M_{B}}{V}$

Given, $w_{B} =$ mass of solute $(B)$ in $g$

$M_{B} = Gram molar mass of B (C_{12} H_{22} O_{11}) = 342 g m o l^{- 1}$

Molarity $= 0.1 M$

Volume $(V) = 2 L$

$\Rightarrow 0.1 = \frac{w_{B} / 342}{2} \Rightarrow w_{B} = 0.1 \times 342 \times 2 g = 68.4 g$

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