SATHEE: Some Basic Concepts of Chemistry - Result Question 85

Some Basic Concepts of Chemistry - Result Question 85

####23. The equivalent weight of $M n S O_{4}$ is half of its molecular weight, when it converts to

$(1988, 1 M)$

(a) $M n_{2} O_{3}$

(b) $M n O_{2}$

(c) $M n O_{4}^{-}$

(d) $M n O_{4}^{2 -}$

Objective Question II (More than one correct option)

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Solution:

Mass of an electron $= 9.108 \times 10^{- 31} k g$

$∵ 9.108 \times 10^{- 31} k g = 1.0$ electron

$∴ 1 k g = \frac{1}{9.108 \times 10^{- 31}}$ electrons $= \frac{10^{31}}{9.108} \times \frac{1}{6.023 \times 10^{23}}$

$= \frac{1}{9.108 \times 6.023} \times 10^{8} mole of electrons$

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