Some Basic Concepts of Chemistry - Result Question 84
####22. The oxidation number of phosphorus in $Ba\left(H _2 PO _2\right) _2$ is
(a) +3
(b) +2
(c) +1
(d) -1
(1988)
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Solution:
- $\quad$ Number of atoms $=$ Number of moles
$\times$ Avogadro’s number $\left(N _A\right)$
Number of atoms in $24 g C=\frac{24}{12} \times N _A=2 N _A$
Number of atoms in $56 g$ of $Fe=\frac{56}{56} N _A=N _A$
Number of atoms in $27 g$ of $Al=\frac{27}{27} N _A=N _A$
Number of atoms in $108 g$ of $Ag=\frac{108}{108} N _A=N _A$
Hence, $24 g$ of carbon has the maximum number of atoms.
