Some Basic Concepts of Chemistry - Result Question 80
####18. The number of moles of $KMnO _4$ that will be needed to react completely with one mole of ferrous oxalate in acidic medium is
(1997)
(a) $\frac{2}{5}$
(b) $\frac{3}{5}$
(c) $\frac{4}{5}$
(d) 1
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Solution:
- From the formula, $M _f=\frac{M _1 V _1+M _2 V _2}{V _1+V _2}$
Given, $V _1=750 mL, M _1=0.5 M$
$$ \begin{aligned} V _2 & =250 mL, M _2=2 M \ & =\frac{750 \times 0.5+250 \times 2}{750+250}=\frac{875}{1000}=0.875 M \end{aligned} $$
