SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 60

####59. The vapour density (hydrogen $= 1$ ) of a mixture consisting of $N O_{2}$ and $N_{2} O_{4}$ is 38.3 at ${26.7}^{\circ} C$ . Calculate the number of moles of $N O_{2}$ in $100 g$ of the mixture.

$(1979, 5 M)$

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Solution:

From the vapour density information

Molar mass $=$ Vapour density $\times 2 (∵$ Molar mass of $H_{2} = 2)$

$= 38.3 \times 2 = 76.6$

Now, let us consider 1.0 mole of mixture and it contains $x$ mole of $N O_{2}$ .

$\Rightarrow 46 x + 92 (1 - x) = 76.6 \Rightarrow x = 0.3348$

Also, in $100 g$ mixture, number of moles $= \frac{100}{76.6}$

$\Rightarrow$ Moles of $N O_{2}$ in mixture $= \frac{100}{76.6} \times 0.3348 = 0.437$

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Some Basic Concepts of Chemistry - Result Question 60

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