Some Basic Concepts of Chemistry - Result Question 58

####57. 5.00mL of a gas containing only carbon and hydrogen were mixed with an excess of oxygen (30mL) and the mixture exploded by means of electric spark. After explosion, the volume of the mixed gases remaining was 25mL.

On adding a concentrated solution of KOH, the volume further diminished to 15mL, the residual gas being pure oxygen. All volumes have been reduced to NTP. Calculate the molecular formula of the hydrocarbon gas. (1979,3M)

Show Answer

Solution:

  1. In the present case, Vn ( all the volumes are measured under identical conditions of temperature and pressure) Hence, the reaction stoichiometry can be solved using volumes as :

CxHy(g)+(x+y4)O2(g)xCO2(g)+y2H2O(l)

volume of CO2(g)+O2(g) (remaining unreacted) =25

Volume of CO2(g) produced

=10mL(15mLOO2 remaining )

1mLCxHy produces xmL of CO2

5mLCxHy will produce 5xmL of CO2=10mL

x=2

Also, 1mLCxHy combines with (x+y4)mL of O2

5mLCxHy will combine with 5(x+y4)mLof O2

5(x+y4)=15(15mL of O2 out of 30mL)

y=4, hence hydrocarbon is C2H4

(remaining unreacted)



NCERT Chapter Video Solution

Dual Pane