Some Basic Concepts of Chemistry - Result Question 45
####45. Find the molarity of water. Given: $\rho=1000 kg / m^{3}$
(2003)
Show Answer
Solution:
- Mass of $1.0 L$ water $=1000 g$
$\Rightarrow \quad$ Molarity $=\frac{1000}{18}=55.56 mol L^{-1}$
####45. Find the molarity of water. Given: $\rho=1000 kg / m^{3}$
(2003)
$\Rightarrow \quad$ Molarity $=\frac{1000}{18}=55.56 mol L^{-1}$
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