Some Basic Concepts of Chemistry - Result Question 36
####36. The weight of $1 \times 10^{22}$ molecules of $CuSO _4 \cdot 5 H _2 O$ is (1991, 1M)
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Solution:
- Molar mass of $CuSO _4 \cdot 5 H _2 O$
$$ \begin{aligned} & =63.5+32+4 \times 16+5 \times 18 \ & =249.5 g \end{aligned} $$
Also, molar mass represents mass of Avogadro number of molecules in gram unit, therefore
$\because 6.023 \times 10^{23}$ molecules of $CuSO _4 \cdot 5 H _2 O$ weigh $249.5 g$
$\therefore 10^{22}$ molecules will weigh $\frac{249.5}{6.023 \times 10^{23}} \times 10^{22}=4.14 g$
