SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 13

####13. $1 g$ of a carbonate $(M_{2} C O_{3})$ on treatment with excess $H C l$ produces 0.01186 mole of $C O_{2}$ . The molar mass of $M_{2} C O_{3}$ in $g m o l^{- 1}$ is

(2017 JEE Main)

(a) 1186

(b) 84.3

(d) 11.86

Show Answer

Solution:

$\underset{1 g}{M_{2} C O_{3}} + 2 H C l ⟶ 2 M C l + \underset{\begin{matrix} 0.01186 mole \end{matrix}}{H_{2} O} + \underset{2}{C O_{2}}$

Number of moles of $M_{2} C O_{3}$ reacted $=$ Number of moles of $C O_{2}$ evolved

$\begin{aligned} \frac{1}{M} = 0.01186 [M = molar mass of M_{2} C O_{3}] & M = \frac{1}{0.01186} = 84.3 g m o l^{- 1} \end{aligned}$

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Some Basic Concepts of Chemistry - Result Question 13

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu