Solid State - Result Question 5
####5. Element ’ $B$ ’ forms ccp structure and ’ $A$ ’ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is
(2019 Main, 8 April I)
(a) $A_2BO_4$
(b) $AB_2O_4$
(c) $A_2B_2O$
(d) $A_4B_2O$
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Answer:
Correct Answer: 5. (b)
Solution:
- The number of element ’ $B$ ’ in the crystal structure $=4 N$
Number of tetrahedral voids $=2 N$
Number of octahedral voids $=N$
$\therefore$ Number of ’ $A$ ’ in the crystal $=\frac{N}{2}=\frac{4}{2}=2$
Number of oxygen $(O)$ atoms $=2 N=2 \times 4=8$
$\therefore$ The structure of bimetallic oxide $=A _2 B _4 O _8=A B _2 O _4$
