SATHEE: Solid State - Result Question 5

Solid State - Result Question 5

####5. Element ’ $B$ ’ forms ccp structure and ’ $A$ ’ occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is

(2019 Main, 8 April I)

(a) $A_{2} B O_{4}$

(b) $A B_{2} O_{4}$

(d) $A_{4} B_{2} O$

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Answer:

Correct Answer: 5. (b)

Solution:

The number of element ’ $B$ ’ in the crystal structure $= 4 N$

Number of tetrahedral voids $= 2 N$

Number of octahedral voids $= N$

$∴$ Number of ’ $A$ ’ in the crystal $= \frac{N}{2} = \frac{4}{2} = 2$

Number of oxygen $(O)$ atoms $= 2 N = 2 \times 4 = 8$

$∴$ The structure of bimetallic oxide $= A_{2} B_{4} O_{8} = A B_{2} O_{4}$

Solid State - Result Question 5

Answer:

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Solid State - Result Question 5

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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