Solid State - Result Question 29

####29. Consider an ionic solid MX with NaCl structure. Construct a new structure (Z) whose unit cell is constructed from the unit cell of MX following the sequential instruction given below. Neglect the charge balance.

(2018 Adv.)

(a) Remove all the anions (X) except the central one

(b) Replace all the face centered cations (M) by anions (X)

(c) Remove all the corner cations (M)

(d) Replace the central anion (X) with cation (M)

The value of ( Number of anions  Number of cations ) in Z is

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Answer:

Correct Answer: 29. (3)

Solution:

  1. The unit cell of initial structure of ionic solid MX looks like

In NaCl type of solids cations (Na+)occupy the octahedral voids while anions (Cl)occupy the face centre positions.

However, as per the demand of problem the position of cations and anions are swapped.

We also know that (for 1 unit cell)

(A) Total number of atoms at FCC=4

(B) Total number of octahedral voids =4

(as no. of atoms at FCC= No. of octahedral voids)

Now taking the conditions one by one

(i) If we remove all the anions except the central one than number of left anions.

=43=1

(ii) If we replace all the face centred cations by anions than effective number of cations will be =43=1

Likewise effective number of anions will be =1+3=4

(iii) If we remove all the corner cations then effective number of cations will be 11=0

(iv) If we replace central anion with cation then effective number of cations will be 0+1=1

Likewise effective number of anions will be 41=3

Thus, as the final outcome, total number of cations present in Z after fulfilling all the four sequential instructions =1

Likewise, total number of anions =3

Hence, the value of  Number of anions  Number of cations =31=3



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