sblock Elements - Result Question 41
####51. Iodine reacts with hot $NaOH$ solution. The products are $NaI$ and ……
$(1980,1 M)$
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Answer:
Correct Answer: 51. $NaIO _3$
Solution:
- $I _2$ disproportionate in alkali giving $NaI$ and $NaIO _3$.