SATHEE: pBlock ElementsII - Result Question 6

pBlock ElementsII - Result Question 6

####6. When the first electron gain enthalpy $(Δ_{e_{g}} H)$ of oxygen is $- 141 k J / m o l$ , its second electron gain enthalpy is

(2019 Main, 9 Jan II)

(a) a positive value

(b) a more negative value than the first

(d) negative, but less negative than the first

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Answer:

Correct Answer: 6. (a)

Solution:

As given, the first electron gain enthalpy of oxygen can be shown as,

$O (g) + e^{-} ⟶ O^{-} (g) Δ e_{g} H_{1} = - 141 k J / m o l$

The expression of second electron gain enthalpy of oxygen will be,

$O^{-} (g) + e^{-} ⟶ O^{2 -} (g) Δ e_{g} H_{2} = + ve$

$Δ e_{g} H_{2}$ of oxygen is positive, i.e. endothermic, because a strong electrostatic repulsion will be observed between highy negative $O^{-}$ and the incoming electron $(e^{-})$ . A very high amount of energy will be consumed (endothermic) by the system to overcome the electrostatic repulsion.

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pBlock ElementsII - Result Question 6

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