pBlock ElementsII 1 Question 48
48. Ammonia, on reaction with hypochlorite anion, can form
(a) $\mathrm{NO}$
(b) $\mathrm{NH} _{4} \mathrm{Cl}$
(c) $\mathrm{N} _{2} \mathrm{H} _{4}$
(d) $\mathrm{HNO} _{2}$
(1999, 3M)
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Answer:
Correct Answer: 48. (c)
Solution:
- $2 \mathrm{NH} _{3}+\mathrm{OCl}^{-} \longrightarrow \mathrm{H} _{2} \mathrm{N}-\mathrm{NH} _{2}+\mathrm{H} _{2} \mathrm{O}+\mathrm{Cl}^{-}$
