p-Block Elements-I - Result Question 39

####10. In compounds of type $E Cl _3$, where $E=B, P, As$ or $Bi$, the angles $Cl-E-Cl$ for different $E$ are in the order

(1999, 2M)

(a) $B>P=As=Bi$

(b) $B>P>As>Bi$

(c) $B<P=As=Bi$

(d) B $<$ P $<$ As $<$ Bi

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Answer:

Correct Answer: 10. (b)

Solution:

  1. In $BCl _3$, bond angle $=120^{\circ}$.

In $PCl _3, AsCl _3$ and $BiCl _3$, central atom is $s p^{3}$ hybridised. Since $P, As$ and $Bi$ are from the same group, bond angle decreases down the group. Hence, overall order of bond angle is :

$$ B>P>As>Bi $$



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