Nuclear Chemistry - Result Question 26
####26. ${ } _{90} Th^{234}$ disintegrates to give ${ } _{82} Pb^{206}$ as the final product. How many alpha and beta particles are emitted during this process?
$(1986,2 M)$
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Solution:
- ${ } _{90} Th^{234} \longrightarrow{ } _{82} Pb^{206}+7{ } _2 He^{4}+6{ } _{-1} e^{0}$
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