####2. A positron is emitted from ${ } _{11}^{23} Na$. The ratio of the atomic mass and atomic number of the resulting nuclide is
(2007, 3M)
(a) $22 / 10$
(b) $22 / 11$
(c) $23 / 10$
(d) $23 / 12$
Correct Answer: 2. (c)
Solution:
$$ { } _{11} Na^{23} \longrightarrow{ } _{+1} e^{0}+{ } _{10} Na^{23} $$
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