Nuclear Chemistry - Result Question 2

####2. A positron is emitted from ${ } _{11}^{23} Na$. The ratio of the atomic mass and atomic number of the resulting nuclide is

(2007, 3M)

(a) $22 / 10$

(b) $22 / 11$

(c) $23 / 10$

(d) $23 / 12$

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Answer:

Correct Answer: 2. (c)

Solution:

  1. The required nuclear reaction is

$$ { } _{11} Na^{23} \longrightarrow{ } _{+1} e^{0}+{ } _{10} Na^{23} $$



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