Nuclear Chemistry - Result Question 15
####15. (a) ${ } _{92}^{235} U+{ } _0 n^{1} \longrightarrow{ } _{52}^{137} A+{ } _{40}^{97} B+\ldots \ldots$
(b) ${ } _{34}^{82} Se \longrightarrow 2{ } _{-1} e^{0}+\ldots \ldots$
$(2005,1 M \times 2=2 M)$
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Answer:
Correct Answer: 15. $(a, c, d)$
Solution:
- (a) ${ } _{92} U^{235}+{ } _0 n^{1} \longrightarrow{ } _{52} A^{137}+{ } _{40} B^{97}+2{ } _0 n^{1}$
(b) ${ } _{34} Se^{82} \longrightarrow 2{ } _{-1} e^{0}+{ } _{36} Kr^{82}$
