Hydrocarbons - Result Question 77
####64. Write the intermediate steps for each of the following reactions :
(i) $C _6 H _5 CH(OH) C \equiv CH \xrightarrow{H _3 O^{+}} C _6 H _5-CH=CH-CHO$
(ii)
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Solution:
- (i) $C _6 H _5-CH-C \equiv CH \xrightarrow{H^{+}} C _6 H _5-\stackrel{+}{O} \stackrel{+}{CH}-C \equiv CH$
$$ \begin{gathered} \stackrel{-H _2 O}{\longrightarrow} C _6 H _5-\stackrel{+}{C} H-C \equiv CH \xrightarrow[\text { (Tautomerisation) }]{\stackrel{H^{+}}{\longrightarrow}} C _6 H _5-CH=C=\underset{O}{C}=CH \end{gathered} $$
unstable enol
(ii)
