Hydrocarbons - Result Question 76
####63. Complete the following reactions with appropriate structures of products/reagents :
$C _6 H _5 CH=CH _2 \xrightarrow{Br _2}[A] \xrightarrow[\text { (ii) } CH _3 I]{\text { (i) } NaNH _2 \text { (3 equivalent) }}[B]$
$(1998,2 M)$
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Solution:
- $C _6 H _5-CH=CH _2+Br _2 \longrightarrow C _6 H _5-\underset{Br}{CH}-\stackrel{\stackrel{Br}{Cr}}{Cr}$
$$ \underset{CH _3 I}{NaNH _2} C _6 H _5-\underset{B}{C \equiv C}-CH _3 $$
