####29. The reaction of $CH _3 CH=CH-OH$ with $HBr$ gives
$(1998,2 M)$
(a) $CH _3 CHBrCH _2$
(b) $CH _3 CHBrCH _2$
(c) $CH _3 CH _2 CHBr$
(d) $CH _3 CH _2 CHBr$
Correct Answer: 29. (a)
Solution:
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