Hydrocarbons - Result Question 40

####23. The reaction of propene with $HOCl$ proceeds via the addition of

(2001)

(a) $H^{+}$in the first step

(c) $OH^{-}$in the first step

(b) $Cl^{+}$in the first step

(d) $Cl^{+}$and $OH^{-}$single step

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Answer:

Correct Answer: 23. (b)

Solution:

  1. $HOCl \longrightarrow HO^{-}+Cl^{+}$

i.e. reaction is initiated by $Cl^{+}$(chloronium ion electrophile)



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