SATHEE: Extraction of Metals - Result Question 44

Extraction of Metals - Result Question 44

####44. Upon heating with $C u_{2} S$ , the reagent(s) that give copper metal is/are

(2014 Adv.)

(a) $C u F e S_{2}$

(b) $C u O$

(d) $C u S O_{4}$

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Solution:

(b) $4 C u O \overset{1100^{\circ} C}{\to} 2 C u_{2} O + O_{2}$

$2 C u_{2} O + C u_{2} S \overset{Δ}{⟶} 6 C u + S O_{2}$

(d) $C u S O_{4} \overset{720^{\circ} C}{\to} C u O + S O_{2} + \frac{1}{2} O_{2}$

$\begin{array}{r} 4 C u O \overset{1100^{\circ} C}{\to} 2 C u_{2} O + O_{2} 2 C u_{2} O + C u_{2} S \overset{Δ}{⟶} 6 C u + S O_{2} \end{array}$

Reaction is believed to proceed as

$\begin{aligned} C u_{2} S & ⇌ 2 C u^{+} + S^{2 -} 2 C u_{2} O & ⇌ 4 C u^{+} + 2 O^{2 -} S^{2 -} + 2 O^{2 -} & ⟼ S O_{2} + 6 e^{-} 6 C u^{+} + 6 e^{-} & ⟶ 6 C u; E_{cell}^{\circ} = 0.52 \end{aligned}$

Here, copper sulphide is reduced to copper metal. Solidified copper has blistered appearance due to evolution of $S O_{2}$ and thus obtained copper is known as blister copper.

Other compounds which give $C u$ are

(i) $C u O$ as $4 C u O \overset{1100^{\circ} C}{\to} 2 C u_{2} O + O_{2}$

$2 C u_{2} O + C u_{2} S \overset{Δ}{⟶} 6 C u + S O_{2}$

(ii) $C u S O_{4}$ as $C u S O_{4} \overset{720^{\circ} C}{\to} C u O + S O_{2} + \frac{1}{2} O_{2}$

$\begin{array}{r} 4 C u O \overset{Δ}{⟶} 2 C u_{2} O + O_{2} 2 C u_{2} O + C u_{2} S \overset{Δ}{⟶} 6 C u + S O_{2} \end{array}$

While $C u F e S_{2}$ will not give $C u$ on heating. The heating in the presence of $O_{2}$ gives $C u_{2} S$ and $F e S$ with the evolution of $S O_{2}$ .

Extraction of Metals - Result Question 44

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Extraction of Metals - Result Question 44

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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