SATHEE: Extraction of Metals - Result Question 42

Extraction of Metals - Result Question 42

####42. Extraction of copper from copper pyrite $(C u F e S_{2})$ involves

(2016 Adv.)

(a) crushing followed by concentration of the ore by froth-floatation

(b) removal of iron as slag

(d) refining of ‘blister copper’ by carbon reduction

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Solution:

$C u F e S_{2}$ (copper pyrite) is converted into copper into following steps:

Step I Crushing (grinding ) followed by concentration by froth-floatation process.

Step II Roasting of ore in the presence of $S i O_{2}$ which removes iron as slag $(F e S i O_{3})$ .

$\begin{aligned} 2 C u F e S_{2} + O_{2} & ⟶ C u_{2} S + 2 F e S + S O_{2} 2 F e S + 3 O_{2} & ⟶ 2 S O_{2} + 2 F e O F e O + S i O_{2} & ⟶ F e S i O_{3} (Slag) \end{aligned}$

Step III Self-reduction in Bessemer converter

$2 C u_{2} S + 3 O_{2} ⟶ 2 C u_{2} O + 2 S O_{2}$

$2 C u_{2} O + C u_{2} S ⟶ 6 C u + S O_{2}$

Copper obtained is blister copper ( $98$ pure).

Step IV Refining of blister copper is done by electrolysis Impure copper-Anode Pure copper- Cathode

At anode $: C u ⟶ C u^{2 +} + 2 e^{-}$

At cathode : $C u^{2 +} + 2 e^{-} ⟶ C u$

Carbon-reduction method is not used. Thus, (d) is incorrect.

Extraction of Metals - Result Question 42

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Extraction of Metals - Result Question 42

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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