Electrochemistry 1 Question 2

2. A solution of $\mathrm{Ni}(\mathrm{NO} _{3}) _{2}$ is electrolysed between platinum electrodes using 0.1 Faraday electricity. How many mole of $\mathrm{Ni}$ will be deposited at the cathode? (2019 Main, 9 April II)

(a) 0.20

(b) 0.10

(c) 0.15

(d) 0.05

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Answer:

Correct Answer: 2. (d)

Solution:

  1. A solution of $\mathrm{Ni}(\mathrm{NO} _{3}) _{2}$ is electrolysed between platinum electrodes using 0.1 Faraday electricity. It means that 0.1 equivalent of $\mathrm{Ni}^{2+}$ will be discharged.

Electrolysis of $\mathrm{Ni}(\mathrm{NO} _{3}) _{2}$ gives

$ \mathrm{Ni}^{2+}+2 e^{-} \longrightarrow \mathrm{Ni} \quad(\text { Atomic mass of } \mathrm{Ni}=58.7) $

Number of equivalents $=$ Number of moles $\times$ number of electrons. $0.1=$ Number of moles $\times 2$

$\therefore$ Number of moles of $\mathrm{Ni}=\frac{0.1}{2}=0.05$



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