SATHEE: Coordination Compounds 2 Question 47

Coordination Compounds 2 Question 47

####49. Amongst the following, the lowest degree of paramagnetism per mole of the compound at $298 K$ will be shown by

(a) $M n S O_{4} \cdot 4 H_{2} O$

(b) $C u S O_{4} \cdot 5 H_{2} O$

(d) $N i S O_{4} \cdot 6 H_{2} O$

$(1988, 2 M)$

Objective Question II

(One or more than one correct option)

Show Answer

Solution:

Salt with least number of unpaired electrons in $d$ - orbital of central metal will show lowest degree of paramagnetism

$M n^{2 +} (3 d^{5}, 5$ unpaired electrons)

$C u^{2 +} (3 d^{9}, 1$ unpaired electrons)

$F e^{2 +} (3 d^{6}, 4$ unpaired electrons $)$

$N i^{2 +}$ ( $3 d^{8}, 2$ unpaired electrons)

Hence, $C u S O_{4} \cdot 5 H_{2} O$ has lowest degree of paramagnetism.

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Coordination Compounds 2 Question 47

Objective Question II

Solution:

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