Coordination Compounds 2 Question 14

####16. The coordination number of Th in $K _4\left[Th\left(C _2 O _4\right) _4\left(OH _2\right) _2\right]$ is $\left(C _2 O _4^{2-}=\right.$ Oxalato $)$

(2019 Main, 11 Jan II)

(a) 14

(b) 10

(c) 8

(d) 6

Show Answer

Solution:

  1. Coordination number is defined as the total number of ligands to which the metal is directly attached.

Here, $C _2 O _4^{2-}$ is a bidentate ligand,

and $H _2 O$ is a monodentate ligand, $H _2 O: \longrightarrow M$

So, total number of sites offered by $C _2 O _4^{2-}$ and $H _2 O$ ligands around $Th(IV)=$ Coordination number of Th (IV)

$$ =4 \times 2\left(\text { by } C _2 O _4^{2-}\right)+2 \times 1\left(\text { by } H _2 O\right)=10 $$



NCERT Chapter Video Solution

Dual Pane