SATHEE: Coordination Compounds 1 Question 25

Coordination Compounds 1 Question 25

####25. The volume (in $m L$ ) of $0.1 M A g N O_{3}$ required for complete precipitation of chloride ions present in $30 m L$ of $0.01 M$ solution of $[C r {(H_{2} O)}_{5} C l^{2}] C l_{2}$ , as silver chloride is close to

(2011)

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Solution:

$m m o l$ of complex $= 30 \times 0.01 = 0.3$

Also, 1 mole of complex $[C r {(H_{2} O)}_{5} C l^{2}] C l_{2}$ gives only two moles of chloride ion when dissolved in solution

$[C r {(H_{2} O)}_{5} C l] C l_{2} ⟶ [C r {(H_{2} O)}_{5} C l^{2 +} + 2 C l^{-}$

$\Rightarrow m m o l$ of $C l^{-}$ ion produced from its $0.3 m m o l = 0.6$

Hence, $0.6 m m o l$ of $A g^{+}$ would be required for precipitation.

$\Rightarrow 0.60 m m o l$ of $A g^{+} = 0.1 M \times V ($ in $m L) \Rightarrow V = 6 m L$

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Coordination Compounds 1 Question 25

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