Coordination Compounds 1 Question 15
####15. The ionisation isomer of $\left[Cr\left(H _2 O\right) _4 Cl\left(NO _2\right)\right] Cl$ is
(a) $\left[Cr\left(H _2 O\right) _4\left(O _2 N\right)\right] Cl _2$
(b) $\left[Cr\left(H _2 O\right) _4 Cl _2\right]\left(NO _2\right)$
(c) $\left[Cr\left(H _2 O\right) _4 Cl(ONO)\right] Cl$
(d) $\left[Cr\left(H _2 O\right) _4 Cl _2\left(NO _2\right)\right] \cdot H _2 O$
(2010)
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Answer:
Correct Answer: 15. $(c, d)$
Solution:
- Ionisation isomers are the complexes that produces different ions in solution, i.e. they have ions interchanged inside and outside the coordination sphere.
$\left[Cr\left(H _2 O\right) _4 Cl\left(NO _2\right)\right] Cl$ and $\left[Cr\left(H _2 O\right) _4 Cl _2\right]\left(NO _2\right)$ have different ions inside and outside the coordinate sphere and they are isomers.
Therefore, they are ionisation isomers.
