SATHEE: Coordination Compounds 1 Question 13

Coordination Compounds 1 Question 13

####13. Geometrical shapes of the complexes formed by the reaction of $N i^{2 +}$ with $C l^{-}, C N^{-}$ and $H_{2} O$ , respectively, are

(2011)

(a) octahedral, tetrahedral and square planar

(b) tetrahedral, square planar and octahedral

(d) octahedral, square planar and octahedral

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Answer:

Correct Answer: 13. (c)

Solution:

$N i^{2 +} + 4 C N^{-} \to {[N i (C N)_{4}]}^{2 -}$

Here, $N i^{2 +}$ has $d^{8}$ -configuration with $C N^{-}$ as strong ligand.

$d^{8}$ -configuration in strong ligand field gives $d s p^{2}$ -hybridisation, hence square planar geometry.

$N i^{2 +} + 4 C l^{-} ⟶ {[N i C l_{4}]}^{2 -}$

Here, $N i^{2 +}$ has $d^{8}$ -configuration with $C l^{-}$ as weak ligand.

$d^{8}$ -configuration in weak ligand field gives $s p^{3}$ -hybridisation, hence tetrahedral geometry. $N i^{2 +}$ with $H_{2} O$ forms ${[N i {(H_{2} O)}_{6}]}^{2 +}$ complex and $H_{2} O$ is a weak ligand.

Therefore, ${[N i {(H_{2} O)}_{6}]}^{2 +}$ has octahedral geometry.

Coordination Compounds 1 Question 13

Answer:

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Coordination Compounds 1 Question 13

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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