Coordination Compounds 1 Question 10

####10. The number of geometric isomers that can exist for square planar $\left[Pt(Cl)(py)\left(NH _3\right)\left(NH _2 OH\right)\right]^{+}$is (py = pyridine).

(a) 2

(b) 3

(c) 4

(d) 6

(2015 Main)

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Answer:

Correct Answer: 10. $(b, d)$

Solution:

  1. $\left[Pt(Cl)(py)\left(NH _3\right)\left(NH _2 OH\right)\right]^{+}$is square planar complex. The structures are formed by fixing a group and then arranging all the groups.

Hence, this complex shows three geometrical isomers.



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