Coordination Compounds 1 Question 10
####10. The number of geometric isomers that can exist for square planar $\left[Pt(Cl)(py)\left(NH _3\right)\left(NH _2 OH\right)\right]^{+}$is (py = pyridine).
(a) 2
(b) 3
(c) 4
(d) 6
(2015 Main)
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Answer:
Correct Answer: 10. $(b, d)$
Solution:
- $\left[Pt(Cl)(py)\left(NH _3\right)\left(NH _2 OH\right)\right]^{+}$is square planar complex. The structures are formed by fixing a group and then arranging all the groups.
Hence, this complex shows three geometrical isomers.
