Chemical Kinetics - Result Question 35
####35. The rate constant for the reaction, $2 N _2 O _5 \longrightarrow 4 NO _2+O _2$ is $3.0 \times 10^{-5} s^{-1}$. If the rate is $2.40 \times 10^{-5} mol L^{-1} s^{-1}$, then the concentration of $N _2 O _5$ (in $mol L^{-1}$ ) is
(2000, 1M)
(a) 1.4
(b) 1.2
(c) 0.04
(d) 0.8
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Answer:
Correct Answer: 35. (d)
Solution:
- The unit of rate constant $\left(t^{-1}\right)$ indicating that the decomposition reaction following first order kinetics.
$$ \begin{aligned} & \Rightarrow \quad \text { Rate }=k\left[N _2 O _5\right] \ & {\left[N _2 O _5\right]=\frac{\text { Rate }}{k}=\frac{2.40 \times 10^{-5}}{3 \times 10^{-5}}=0.8 M} \end{aligned} $$
