Chemical Kinetics - Result Question 31
####31. (A) follows first order reaction, $(A) \rightarrow$ product. Concentration of $A$, changes from $0.1 M$ to $0.025 M$ in $40 min$. Find the rate of reaction of $A$ when concentration of $A$ is $0.01 M$.
(2004, 1M)
(a) $3.47 \times 10^{-4} M min^{-1}$
(b) $3.47 \times 10^{-5} M min^{-1}$
(c) $1.73 \times 10^{-4} M min^{-1}$
(d) $1.73 \times 10^{-5} M min^{-1}$
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Answer:
Correct Answer: 31. (d)
Solution:
- For first order reaction,
$k=\frac{2.303}{t} \log \frac{a}{a-x}=\frac{2.303}{40} \log \frac{0.1}{0.025}=3.46 \times 10^{-2}$
Rate $=[k] A=3.46 \times 10^{-2} \times 0.01=3.46 \times 10^{-4}$
