Chemical Bonding - Result Question 90
####66. The sum of the number of lone pairs of electrons on each central atom in the following species is
$\left[TeBr _6\right]^{2-},\left[BrF _2\right]^{+}, SNF _3$ and $\left[XeF _3\right]^{-}$
(Atomic numbers : $N=7, F=9, S=16, Br=35$,
$Te=52, Xe=54)$
(2017 Adv.)
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Answer:
Correct Answer: 66. $F$
Topic 3
| 1. (b) | 2. (c) | 3. (a) | 4. (a) |
|---|---|---|---|
| 5. (a) | 6. (c) | 7. (d) | 8. (d) |
| 9. (b) | 10. (c) | 11. (b) | 12. (c) |
| 13. (b) | 14. (a) | 15. (d) | 16. (b) |
| 17. (a) | 18. (c) | 19. (d) | 20. $(a, c)$ |
| 21. $(a, b, d)$ | 22. $(a, b)$ | 23. (a) |
Solution:
| S.N. | Species | No. of $\sigma$-bonds with central atom |
No. of L.P at central atom |
|---|---|---|---|
| (i) | $\operatorname{In}\left[TeBr _6\right]^{2-}$ | 6 | 1 |
| (ii) | $\operatorname{In}\left[BrF _2\right]^{+}$ | 2 | 2 |
| (iii) | In $SNF _3$ | 4 | 0 |
| (iv) | $\operatorname{In}\left[XeF _3\right]^{-}$ | 3 | 3 |
