Chemical Bonding - Result Question 74

####50. Match each of the diatomic molecules in Column I with its property/properties in Column II.

(2009)

Column I ColumnII
A. $B _2$ p. Paramagnetic
B. $N _2$ q. Undergoes oxidation
C. $O _2^{-}$ r. Undergoes reduction
D. $O _2$ s. Bond order $\geq 2$
t. Mixing of ’ $s$ ’ and ’ $p$ ’ orbitals

Codes

A B C D
(a) q, r, s p, r, t, s q, r, t p, q, t
(b) p, q, r, t q, r, s, t p, q, r, t p, r, s, t
(c) q, r, s, t p, q,r r, s, t p, q, r, t
(d) p, q, s, t p, q, s p, t q, r, t

Fill in the Blanks

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Answer:

Correct Answer: 50. (b) $A \rightarrow p, q, r, t ; B \rightarrow q, r, s, t ; C \rightarrow p, q, r, t ; D \rightarrow p, r, s, t$

Solution:

  1. (A) $B _2: \sigma 1 s^{2} \stackrel{}{\sigma} 1 s^{2} \sigma 2 s^{2} \stackrel{}{\sigma} 2 s^{2}\left|\begin{array}{l}\pi 2 p _y^{1} \ \pi 2 p _z^{1}\end{array}\right|$ paramagnetic.

Bond order $=\frac{6-4}{2}=1$

Bond is formed by mixing of $s$ and $p$ orbitals.

$B _2$ undergoes both oxidation and reduction as

$$ \begin{aligned} & B _2+O _2 \xrightarrow{\text { Heat }} B _2 O _3 \quad \text { (Oxidation) } \ & B _2+H _2 \longrightarrow B _2 H _6 \text { (Reduction) } \end{aligned} $$

(B) $N _2: \sigma 1 s^{2}{ }^{} \sigma 1 s^{2} \sigma 2 s^{2}{ }^{} \sigma 2 s^{2} \sigma 2 p _x^{2}\left|\begin{array}{l}\pi 2 p _y^{2} \ 10-4\end{array}\right|$ diamagnetic.

Bond order $=\frac{10-4}{2}=3>2$

$N _2$ undergoes both oxidation and reduction as

$$ \begin{aligned} N _2+O _2 & \stackrel{\Delta}{\longrightarrow} NO \ N _2+3 H _2 & \stackrel{\text { Catalyst }}{\longrightarrow} NH _3 \end{aligned} $$

In $N _2$, bonds are formed by mixing of $s$ and $p$ orbitals.

(C) $O _2^{-}: \left.\sigma 1 s^{2} \stackrel{}{\sigma} 1 s^{2} \sigma 2 s^{2} \stackrel{}{\sigma} 2 s^{2} \sigma 2 p _x^{2}\left|\begin{array}{ll}\pi 2 p _y^{2} \ \pi 2 p _z^{2}\end{array}\right| \begin{aligned} & * \ & \pi 2 p _y^{2}\end{aligned} \right\rvert, \stackrel{}{} 2 p _x^{0}$

Paramagnetic with bond order $=1.5 . O _2^{-}$undergoes both oxidation and reduction and bond involves mixing of $s$ and $p$-orbitals.

(D) $O _2: \sigma 1 s^{2} \stackrel{}{\sigma} 1 s^{2} \sigma 2 s^{2} \stackrel{}{\sigma} 2 s^{2} \sigma 2 p _x^{2}\left|\begin{array}{l}\pi 2 p _y^{2} \ \pi 2 p _z^{2}\end{array}\right| \begin{aligned} & \pi \ & \pi 2 p _z^{1}\end{aligned}|\stackrel{}{1}| \stackrel{}{\sigma} 2 p _x^{0}$

Paramagnetic with bond order $=2$.

$O _2$ undergoes reduction and the bond involves mixing of $s$ and $p$-orbitals.



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