Chemical and Ionic Equilibrium - Result Question 9

####9. The values of KpKC for the following reactions at 300K are, respectively (At 300K,RT=24.62dm3atmmol1 )

N2(g)+O2(g)2NO(g) N2O4(g)2NO2(g) N2(g)+3H2(g)2NH3(g)

(2019 Main, 10 Jan I)

(a) 1,24.62dm3atmmol1,606.0dm6atm2mol2

(b) 1,24.62dm3atmmol1,1.65×103dm6atm2mol2

(c) 24.62dm3atmmol1,606.0dm6atm2mol2, 1.65×103dm6atm2mol2

(d) 1,4.1×102dm3atm1mol,606dm6atm2mol2

10 Consider the following reversible chemical reactions,

A2(g)+B2(g)K12AB(g) 6AB(g)K23A2(g)+3B2(g)

The relation between K1 and K2 is (2019 Main, 9 Jan II)

(a) K2=K13

(b) K1K2=3

(c) K2=K13

(d) K1K2=13

Show Answer

Solution:

  1. We know that, the relationship between Kp and KC of a chemical equilibrium state (reaction) is

Kp=KC(RT)ΔngKpKC=(RT)Δng

where, Δng=ΣnProducts ΣnReactants 

(i) N2(g)+O2(g)2NO(g)

(RT)2(1+1)=(RT)0=1

(ii) N2O4(g)2NO2(g)

(RT)21=RT=24.62dm3atmmol1

(iii) N2(g)+3H2(g)2NH3(g)

(RT)2(3+1)=(RT)2

=1(24.62dm3atmmol1)2 =1.649×103dm6atm2mol2



NCERT Chapter Video Solution

Dual Pane