Chemical and Ionic Equilibrium - Result Question 41

####41. If equilibrium constant for the reaction, $A _2+B _2 \rightleftharpoons 2 A B$, is $K$, then for the backward reaction $A B \rightleftharpoons \frac{1}{2} A _2+\frac{1}{2} B _2$, the equilibrium constant is $\frac{1}{K}$.

$(1984,1 M)$

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Solution:

  1. It is $\frac{1}{\sqrt{K}}$.


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