SATHEE: Chemical and Ionic Equilibrium

Chemical and Ionic Equilibrium - Result Question 19

####19. At constant temperature, the equilibrium constant $(K_{p})$ for the decomposition reaction, $N_{2} O_{4} ⇌ 2 N O_{2}$ , is expressed by $K_{p} = \frac{4 x^{2} p}{(1 - x^{2})}$ , where, $p =$ pressure, $x =$ extent of decomposition. Which one of the following statement is true?

(2001, 1M)

(a) $K_{p}$ increases with increase of $p$

(b) $K_{p}$ increases with increase of $x$

(d) $K_{p}$ remains constant with change in $p$ and $x$

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Solution:

$\underset{1 - x}{N_{2} O_{4}} ⇌ \underset{2 x}{2 N O_{2}}, K_{p} = \frac{4 x^{2} p}{1 - x^{2}} \cdot K_{p}$ is function of temperature only, does not change with either $p$ or $x$ .

Chemical and Ionic Equilibrium - Result Question 19

Solution:

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Chemical and Ionic Equilibrium - Result Question 19

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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