Carboxylic Acids and their Derivatives - Result Question 53
####39. An ester $A\left(C _4 H _8 O _2\right)$, on treatment with excess methyl magnesium chloride followed by acidification, gives an alcohol $B$ as the sole organic product. Alcohol $B$, on oxidation with $NaOCl$ followed by acidification, gives acetic acid. Deduce the structures of $A$ and $B$. Show the reactions involved.
(1998)
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Solution:
39.
$$ \xrightarrow{NaOCl} CH _3 COOH+CHCl _3 $$
