Carboxylic Acids and their Derivatives - Result Question 25

####11. When propionic acid is treated with aqueous sodium bicarbonate, $CO _2$ is liberated. The $C$ of $CO _2$ comes from

(a) methyl group

$(1999,2 M)$

(b) carboxylic acid group

(c) methylene group

(d) bicarbonate group

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Answer:

Correct Answer: 11. (b)

Solution:

  1. $CH _3-CH _2-COOH+NaH \stackrel{}{C} O _3 \longrightarrow CH _3 CH _2 COONa$ $+H _2 O+\stackrel{}{C} O _2$


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