Carboxylic Acids and their Derivatives - Result Question 13

####13. The desired product $X$ can be prepared by reacting the major product of the reactions in List-I with one or more appropriate reagents in List-II.

(given, order of migratory aptitude : aryl $>$ alkyl $>$ hydrogen)

$X$

(2018 Adv.)

Q.

The correct option is

(a) $P \rightarrow 1$; $Q \rightarrow 2,3 ; R \rightarrow 1,4 ; S \rightarrow 2,4$

(b) $P \rightarrow 1,5 ; Q \rightarrow 3,4 ; R \rightarrow 4,5 ; S \rightarrow 3$

(c) $P \rightarrow 1,5 ; Q \rightarrow 3,4 ; R \rightarrow 5 ; S \rightarrow 2,4$

(d) $P \rightarrow 1,5 ; Q \rightarrow 2,3 ; R \rightarrow 1,5 ; S \rightarrow 2,3$

Subjective Questions

Show Answer

Answer:

Correct Answer: 13. (c)

Solution:

  1. (d)

The correct match is 1 i.e., $I _2, NaOH$ and 5 i.e., $NaOBr$ The reactions proceed as

For Q, i.e. $NH _2 \overbrace{Ph}^{Ph} \underset{Me}{H} OH+HNO _2$

The correct match is 2 i.e. $\left[Ag\left(NH _3\right) _2\right] OH$ and 3 i.e., Fehling’s solution.

The reactions proceed as

For $R$, i.e. $\underset{Me}{HO \underset{Me}{>}} \underset{OH}{Ph}+H _2 SO _4$

The correct match is 1,5 again. The reaction proceed as

For S, i.e. ${ } _{Ph}^{Br \underbrace{Ph} _{Me}}$

The correct match is 2,3 .

The reaction proceed as

Rest procedure is same as seen for $Q$ above i.e., via oxidation.



NCERT Chapter Video Solution

Dual Pane