Carboxylic Acids and their Derivatives - Result Question 13
####13. The desired product $X$ can be prepared by reacting the major product of the reactions in List-I with one or more appropriate reagents in List-II.
(given, order of migratory aptitude : aryl $>$ alkyl $>$ hydrogen)
$X$
(2018 Adv.)
Q.
The correct option is
(a) $P \rightarrow 1$; $Q \rightarrow 2,3 ; R \rightarrow 1,4 ; S \rightarrow 2,4$
(b) $P \rightarrow 1,5 ; Q \rightarrow 3,4 ; R \rightarrow 4,5 ; S \rightarrow 3$
(c) $P \rightarrow 1,5 ; Q \rightarrow 3,4 ; R \rightarrow 5 ; S \rightarrow 2,4$
(d) $P \rightarrow 1,5 ; Q \rightarrow 2,3 ; R \rightarrow 1,5 ; S \rightarrow 2,3$
Subjective Questions
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Answer:
Correct Answer: 13. (c)
Solution:
- (d)
The correct match is 1 i.e., $I _2, NaOH$ and 5 i.e., $NaOBr$ The reactions proceed as
For Q, i.e. $NH _2 \overbrace{Ph}^{Ph} \underset{Me}{H} OH+HNO _2$
The correct match is 2 i.e. $\left[Ag\left(NH _3\right) _2\right] OH$ and 3 i.e., Fehling’s solution.
The reactions proceed as
For $R$, i.e. $\underset{Me}{HO \underset{Me}{>}} \underset{OH}{Ph}+H _2 SO _4$
The correct match is 1,5 again. The reaction proceed as
For S, i.e. ${ } _{Ph}^{Br \underbrace{Ph} _{Me}}$
The correct match is 2,3 .
The reaction proceed as
Rest procedure is same as seen for $Q$ above i.e., via oxidation.
