Atomic Structure - Result Question 79
####55. Match the entries in Column I with the correctly related quantum number(s) in Column II.
$(2008,6 M)$
| Column I | Column II | ||
|---|---|---|---|
| A. | Orbital angular momentum of the electron in a hydrogen-like atomic orbital. |
p. | Principal quantum number |
| B. | A hydrogen-like one-electron wave function obeying Pauli’s principle. |
q. | Azimuthal quantum number |
| C. | Shape, size and orientation of hydrogen-like atomic orbitals. |
r. | Magnetic quantum number |
| D.Probability density of electron at the nucleus in hydrogen-like atom. |
s. | Electron spin quantum number |
Fill in the Blanks
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Answer:
Correct Answer: 55. $Cr=[Ar] 3 d^{5}, 4 s^{1}$
Solution:
- A. Orbital angular momentum
$$ (L)=\sqrt{l(l+1)} \frac{h}{2 \pi} $$
i.e. $L$ depends on azimuthal quantum number only.
B. To describe a one electron wave function, three quantum numbers $n, l$ and $m$ are needed. Further to abide by Pauli exclusion principle, spin quantum number $(s)$ is also needed.
C. For shape, size and orientation, only $n, l$ and $m$ are needed.
D. Probability density $\left(\psi^{2}\right)$ can be determined if $n, l$ and $m$ are known.
