Aromatic Aldehydes Ketones and Acids - Result Question 24
####28. The Compound $R$ is
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Answer:
Correct Answer: 28. (a)
Solution:
- (a) Given,
(i) $C _{11} H _{12} O _2 \xrightarrow{\text { Oxidation }}$ Dibasic acid
(An organic acid ’ $P$ ‘)
This indicates the presence of alkyl or alkenyl branch in $P$ along with $-COOH$ group.
(ii) Dibassic acid produced by oxidation of $P$
This indicates presence of benzene ring in $P$; as concluded from the structure of dacron given below.
Attachment of - $COO$ group in dacron also confirm the para position of branch with respect to $-COOH$ group in $P$.
This reaction confirms the presence of multiple bonded branch i.e., alkenyl group in $P$. Thus $P$ can be
IUPAC name : 4-(2-methyl) prop-l-enyl benzoic acid Now look for the reactions
$$ \begin{aligned} & \text { 1. } H _2 / Pd-C \ & \text { Given, } P \xrightarrow[\text { 3. } MeMgBr, CdCl _2]{\stackrel{\text { 2. } SOCl _2}{\longrightarrow}} Q \end{aligned} $$
So,
$$ \text { Further, } \quad Q \underset{\substack{\text { 3. } CO _2 \text { (Dry ice) } \ \text { 4. } H _3 O^{+}}}{\substack{\text { 1. } HCl \ 2 . Mg / Et _2 O}} R $$