Alkyl Halides - Result Question 58

####58. Write the structures of the products :

$$ C _6 H _5 CH _2 CHClC _6 H _5 \xrightarrow{\text { Alc. } KOH} $$

(1998, 2M)

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Solution:

  1. $C _6 H _5 CH _2-\underset{Cl}{CH}-C _6 H _5 \xrightarrow[\text { E2 }]{\text { Alc. } KOH} C _6 H _5-CH=CH-C _6 H _5$


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