SATHEE: Alcohols and Ethers - Result Question 6

Alcohols and Ethers - Result Question 6

####9. Which is the most suitable reagent for the following transformation?

(2019 Main, 10 Jan II)

$C H_{3} - C H = C H - C H_{2} C O_{2} H$

(a) Tollen’s reagent

(b) $I_{2} / N a O H$

(d) $C r O_{2} C l_{2} / C S_{2}$

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Answer:

Correct Answer: 9. (b)

Solution:

The most suitable reagent to carry out given transformation is $I_{2} / N a O H$

$\underset{6}{C H_{3}} \underset{5}{C} H = \underset{4}{C} H - C_{3} H_{2} - \underset{2}{C} O H - \underset{1}{C} H_{3} \to_{(Oxidative cleavage)}^{Strong oxidation, [O]}$

$\underset{6}{C H_{3}} - \underset{5}{C} H = \underset{4}{C} H - \underset{3}{C H_{2}} - \underset{2}{C} - O H$

Here, the haloform reaction will give following reaction:

(i) Tollen’s reagent $(A g N O_{3} + N H_{4} O H)$ is a mild oxidising agent. It does not react with $- C H - C H_{3}$ group

$(2^{\circ}$ -alcohol).

(ii) Alkaline $K M n O_{4}$ cannot perform the oxidative cleavage, rather it will hydroxylate the $C = C$ .

(iv) $C r O_{2} C l_{2} / C S_{2}$ will not react here.

Alcohols and Ethers - Result Question 6

Answer:

$(2^{\circ}$ -alcohol).

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Alcohols and Ethers - Result Question 6

Answer:

(2∘-alcohol).

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Medical Preparation

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Other Resources

Syllabus

Test Platform

Sample Mock Test

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$(2^{\circ}$ -alcohol).