Alcohols and Ethers - Result Question 16
####19. Compound ’ $A$ ’ (molecular formula $C _3 H _8 O$ ) is treated with acidified potassium dichromate to form a product ’ $B$ ’ (molecular formula $C _3 H _6 O$ ) ’ $B$ ’ forms a shining silver mirror on warming with ammoniacal silver nitrate. ’ $B$ ’ when treated with an aqueous solution of $H _2 NCONHNH _2$ and sodium acetate gives a product ’ $C$ ‘. Identify the structure of ’ $C$ ‘.
(a) $CH _3 CH _2 CH=NNHCONH _2$
$(2002,3 M)$
(b) $H _3 C-\underset{CH _3}{C}=NNHCONH _2$
(c)
(d) $CH _3 CH _2 OH+NCONHNH _2$
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Answer:
Correct Answer: 19. $(a)$
Solution:
- $A$ is an alcohol and its oxidation product gives Tollen’s test, i.e. $B$ must be an aldehyde $\left(CH _3 CH _2 CHO\right)$.
$$ \begin{aligned} CH _3 CH _2 CHO+\underset{\text { semicarbazide }}{H _2 NHN-CO-} NH _2 & \ CH _3 CH _2-CH & =N-NH-CONH _2 \end{aligned} $$