Semiconductors Question 10
Question 10 - 2024 (31 Jan Shift 2)
The output of the given circuit diagram is
| A | B | $Y$ | |
|---|---|---|---|
| 0 | 0 | 0 | |
| (1) | 1 | 0 | 0 |
| 0 | 1 | 0 | |
| 1 | 1 | 1 | |
| A | B | $Y$ | |
| 0 | 0 | 0 | |
| (2) | 1 | 0 | 1 |
| 0 | 1 | 1 | |
| 1 | 1 | 0 | |
| A | $B$ | $Y$ | |
| 0 | 0 | 0 | |
| (3) | 1 | 0 | 0 |
| 0 | 1 | 0 | |
| 1 | 1 | 0 | |
| $\mathrm{A}$ | $B$ | $\mathrm{Y}$ | |
| 0 | 0 | 0 | |
| (4) | 1 | 0 | 0 |
| 0 | 1 | 1 | |
| 1 | 1 | 0 |
Show Answer
Answer: (3)
Solution:
If $\mathrm{A}=0 ; \overline{\mathrm{A}}=1$
$\mathrm{A}=1 ; \overline{\mathrm{A}}=0$
$\mathrm{B}=0 ; \overline{\mathrm{B}}=1$
$\mathrm{B}=1 ; \overline{\mathrm{B}}=0$
$\mathrm{Y}=\overline{(\mathrm{A}+\overline{\mathrm{B}})+(\overline{\mathrm{A}}+\mathrm{B})}=\overline{(1+1)}=0$
