Magnetic Effects Of Current Question 9
Question 9 - 2024 (29 Jan Shift 2)
A charge of $4.0 \mu \mathrm{C}$ is moving with a velocity of $4.0 \times 10^{6} \mathrm{~ms}^{-1}$ along the positive y-axis under a magnetic field $\vec{B}$ of strength $(2 \hat{k})$ T. The force acting on the charge is $x \hat{i} N$. The value of $x$ is
Show Answer
Answer: (32)
Solution:
$\mathrm{q}=4 \mu \mathrm{C}, \overrightarrow{\mathrm{v}}=4 \times 10^{6} \hat{\mathrm{j} m} / \mathrm{s}$
$\overrightarrow{\mathrm{B}}=2 \mathrm{k} \hat{T}$
$\overrightarrow{\mathrm{F}}=\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})$
$=4 \times 10^{-6}\left(4 \times 10^{6} \hat{\mathrm{j}} \times 2 \hat{\mathrm{k}}\right)$
$=4 \times 10^{-6} \times 8 \times 10^{6} \hat{\mathrm{i}}$
$\overrightarrow{\mathrm{F}}=32 \hat{\mathrm{i} N}$
$\mathrm{x}=32$
