Haloalkanes And Haloarenes Question 6
Question 6 - 2024 (27 Jan Shift 2)
Identify B formed in the reaction.
$\mathrm{Cl}-\left(\mathrm{CH}{2}\right){4}-\mathrm{Cl} \xrightarrow{\text { excess } \mathrm{NH}_{3}} \mathrm{~A} \xrightarrow{\mathrm{NaOH}}$
$\mathrm{B}+\mathrm{H}_{2} \mathrm{O}+\mathrm{NaCl}$
(1)
(2) $\mathrm{H}{2} \mathrm{~N}-\left(\mathrm{CH}{2}\right){4}-\mathrm{NH}{2}$
(3) $\stackrel{+}{\mathrm{Cl}} \mathrm{H}{3}-\left(\mathrm{CH}{2}\right){4}-\stackrel{+}{\mathrm{N}} \mathrm{H}{3} \mathrm{Cl}^{-}$
(4)
Show Answer
Answer (2)
Solution
Formula: Nucleophilic-Substitution-Reaction
$\mathrm{Cl}-\left(\mathrm{CH}{2}\right){4}-\mathrm{Cl} \xrightarrow[\mathrm{NH}{3}]{\text { excess }} \mathrm{Cl}^{-} \stackrel{\oplus}{\mathrm{N}} \mathrm{H}{3}-\left(\mathrm{CH}{2}\right){4} \stackrel{\oplus}{\mathrm{N}} \mathrm{H}_{3} \mathrm{Cl}^{-}$
