SATHEE: Work Power and Energy 5 Question 5

Work Power and Energy 5 Question 5

7. A particle is placed at the origin and a force $F = k x$ is acting on it (where, $k$ is a positive constant). If $U (0) = 0$ , the graph of $U (x)$ versus $x$ will be (where, $U$ is the potential energy function)

(2004, 2M) (a)

(c)

(b)

(d)

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Answer:

Correct Answer: 7. (a)

Solution:

From $F = - \frac{d U}{d x}$

$\begin{aligned} \int_{0}^{U (x)} d U = - \int_{0}^{x} F d x = - \int_{0}^{x} (k x) d x \\ ∴ & U (x) = - \frac{k x^{2}}{2} as U (0) = 0 \end{aligned}$

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Work Power and Energy 5 Question 5

7. A particle is placed at the origin and a force $F = k x$ is acting on it (where, $k$ is a positive constant). If $U (0) = 0$ , the graph of $U (x)$ versus $x$ will be (where, $U$ is the potential energy function)

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Work Power and Energy 5 Question 5

7. A particle is placed at the origin and a force F=kx is acting on it (where, k is a positive constant). If U(0)=0, the graph of U(x) versus x will be (where, U is the potential energy function)

Answer:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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7. A particle is placed at the origin and a force $F = k x$ is acting on it (where, $k$ is a positive constant). If $U (0) = 0$ , the graph of $U (x)$ versus $x$ will be (where, $U$ is the potential energy function)